7b^2=-35b-28

Solution for 7b^2=-35b-28 equation:

7b^2=-35b-28

We move all terms to the left:

7b^2-(-35b-28)=0

We get rid of parentheses

7b^2+35b+28=0

a = 7; b = 35; c = +28;
Δ = b2-4ac
Δ = 352-4·7·28
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-21}{2*7}=\frac{-56}{14}
=-4
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+21}{2*7}=\frac{-14}{14}
=-1
$